Question

pre calc

Answer 1

@extrinix

Answer 2

So, the equation of a circle looks like this.
\(\color{tomato}{(x – h)^2 + (y – k)^2 = r^2}\)

So, the center point that we are given is \((2,3)\), which would be your \(h\) and \(k\).
\(\color{yellow}{(x - 2)^2 + (y – 3)^2 = r^2}\)

Now, the tangent to the x-axis would be where the circle comes upon the axis, so presumably that would be \((3,0)\), which would make the radius \(2\).
\(\color{lime}{(x - 2)^2 + (y – 3)^2 = 2^2}\)

So now all you would do is solve what \(2^2\) is, which is \(4\).
\(\color{cyan}{(x - 2)^2 + (y – 3)^2 = 4}\)

Answer 3

the equations is 4?

Answer 4

It's the whole thing, it states "equation".

Answer 5

(x−2)2+(y–3)2=4 is the equation

Answer 6

its incorrect