The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is the width of the rectangle. Can the perimeter of the rectangle be 60 units when its width is 11 units and its length is 24 units?

No. If the length is 24 units and the width is 11 units, the perimeter would be P = 48 + 22 = 70 units, not 60.
No. If the length is 24 units and the width is 11 units, the perimeter would be P = 24 + 22 = 66 units, not 60.
Yes. If the perimeter is 60 units and the width is 11 units, then P + W is greater than 48.
Yes. If the length is 24 units and the width is 11 units, then P = 2L + 2W = 60.

Question

The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is the width of the rectangle. Can the perimeter of the rectangle be 60 units when its width is 11 units and its length is 24 units?

No. If the length is 24 units and the width is 11 units, the perimeter would be P = 48 + 22 = 70 units, not 60.
 No. If the length is 24 units and the width is 11 units, the perimeter would be P = 24 + 22 = 66 units, not 60.
 Yes. If the perimeter is 60 units and the width is 11 units, then P + W is greater than 48.
 Yes. If the length is 24 units and the width is 11 units, then P = 2L + 2W = 60.

Gucchi · Answer

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