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the perimeter of a rectangle is 66m. one side is 15 m longer than the double other side. setup and solve a system of equations to find the dimensions of the rectangle. pls explain how u got the steps. ty.
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*66 m
let one side=x other side=2x+15 Perimeter=2[(2x+15)+x]=2(2x+15+x)=2(3x+15)=6x+30 6x+30=66 6x=66-30=36 x=36/6=? this is one side . find other side by substituting the value of x in 2x+15
what is the value of x?
36/6=6
do i substitute the value of x into the equation 2[(2x+15)+x]=2(2x+15+x)=2(3x+15)=6x+30 to get the answer?
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one side=x=36/6=6 m other side=2x+15=2(6)+15=12+15=27 m
okay ty
yw
@surjithayer wrote:
let one side=x
other side=2x+15
Perimeter=2[(2x+15)+x]=2(2x+15+x)=2(3x+15)=6x+30
6x+30=66
6x=66-30=36
x=36/6=?
this is one side .
find other side by substituting the value of x in 2x+15
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