Mathematics
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KyledaGreat:
g(x) = x^2 + x − 6
Step 2 of 2 : Sketch the graph by identifying where the graph is positive and where the graph is negative.
Select the area above the axis to plot the positive curve for that region, and select the area below the axis to plot the negative curve for that region. Use the Reset button to remove all curves.
4 years ago
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jhonyy9:
so like the first step try get the zeros of this quadratic
4 years ago
KyledaGreat:
4 years ago
KyledaGreat:
is this right ?
4 years ago
jhonyy9:
what are the roots of this quadratic ?
4 years ago
KyledaGreat:
x = 2, -3
4 years ago
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jhonyy9:
do you can factoriz it completly ?
4 years ago
KyledaGreat:
no
4 years ago
jhonyy9:
@kyledagreat wrote:
x = 2, -3
i think not really
4 years ago
jhonyy9:
-3 +2 = -1 not +1
4 years ago
jhonyy9:
@jhonyy9 wrote:
-3 +2 = -1 not +1
for the b value
4 years ago
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jhonyy9:
maybe this
(x+3)(x-2) = ?
4 years ago
jhonyy9:
this is true ?
4 years ago
KyledaGreat:
yes sir
4 years ago
jhonyy9:
yes so from this result that your graph is right but you need be sure in your calcule
4 years ago
jhonyy9:
step 2 . ???
4 years ago
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KyledaGreat:
umm
4 years ago
KyledaGreat:
i don't think so
4 years ago
jhonyy9:
you need select these areas
4 years ago
KyledaGreat:
oh that's true ok
4 years ago
jhonyy9:
Step 2 of 2 : Sketch the graph by identifying where the graph is positive and where the graph is negative.
4 years ago
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KyledaGreat:
okay , was it right to have done the graph based on the picture ?
4 years ago
jhonyy9:
yes right but now you need solve the point 2
4 years ago
jhonyy9:
Step 2 of 2 : Sketch the graph by identifying where the graph is positive and where the graph is negative.
this ...
4 years ago
jhonyy9:
use your graph so this is easy
4 years ago
KyledaGreat:
how could i do that
4 years ago
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jhonyy9:
do you know where the graph is positive ? and where is negativ ?
4 years ago
KyledaGreat:
I don’t believe so
4 years ago
KyledaGreat:
4 years ago
KyledaGreat:
is it like that ?
4 years ago
KyledaGreat:
4 years ago
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KyledaGreat:
are any of them right that i just did ?
4 years ago
KyledaGreat:
jhonny ?
4 years ago
jhonyy9:
positive right but negativ not marked right
4 years ago
KyledaGreat:
which one
4 years ago
jhonyy9:
on the first one posted image with vectors
4 years ago
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jhonyy9:
the second negativ quadrant is on the right corner down
4 years ago
jhonyy9:
Step 2 of 2 : Sketch the graph by identifying where the graph is positive and where the graph is negative.
4 years ago
KyledaGreat:
4 years ago
jhonyy9:
what you marked there ? positive - negativ parts ???
4 years ago
KyledaGreat:
yes
4 years ago
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KyledaGreat:
does it look like it
4 years ago
jhonyy9:
please mark it with plus or minus signs
4 years ago
KyledaGreat:
i'm sorry for the bluriness , it couldn't focus
4 years ago