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Mathematics 9 Online
Chickentender37:

help pls

Chickentender37:

surjithayer:

3x+5y+z=9 ...(1) -4y-z=0 z=-4y ...(2) 2x+3y-4z=6 ...(3) put the value of z from (2) in (1) and (3) 3x+5y-4y=9 3x+y=9 y=9-3x (4) 2x+3y-4(-4y)=6 2x+3y+16y=6 2x+19y =6 (5) 2x+19(9-3x)=6 2x+171-57x=6 -55x=6-171=-165 x=-165/-55=3 y=9-3(3)=9-9=0 z=-4y=-4(0)=0 so solution is (3,0,0)

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