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need help, geometry
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be warned, i'm no good with math
a+b=c
or in this case, 2div5+2div5=h
although, it may also be sqrt2(5)+sqrt2(5)=h
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huh?
Politely disagree with the previous response The Pythagorean theorem is a^2 + b^2 = c^2 not simply a + b = c Therefore, since your legs are each 5sqrt(2): h^2 = (5sqrt(2))^2 + (5sqrt(2))^2 Solve for h Alternatively: since we have a 45-45-90 triangle, the hypotenuse is simply sqrt(2) times a leg So h = 5sqrt(2) * sqrt(2) = ?
5?
@vocaloid wrote:
Politely disagree with the previous response
The Pythagorean theorem is a^2 + b^2 = c^2 not simply a + b = c
Therefore, since your legs are each 5sqrt(2):
h^2 = (5sqrt(2))^2 + (5sqrt(2))^2
Solve for h
Alternatively: since we have a 45-45-90 triangle, the hypotenuse is simply sqrt(2) times a leg
So h = 5sqrt(2) * sqrt(2) = ?
sqrt(2) * sqrt(2) = 2 So 5sqrt(2) * sqrt(2) = 10
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