What is the magnetic force acting on an electron if its speed is 3.0 × 106 meters/second and the direction is perpendicular to a magnetic field of 0.020 teslas? The value of q = -1.6 × 10-19 coulombs.
The answer choices are...
A.F = 0 newtons
B.F = -6.0 × 10-15 newtons
C.F = -9.6 × 10-15 newtons
D.F = -3.0 × 10-16 newtons
E. F = -3.2 × 10-21 newtons

Question

What is the magnetic force acting on an electron if its speed is 3.0 × 106 meters/second and the direction is perpendicular to a magnetic field of 0.020 teslas? The value of q = -1.6 × 10-19 coulombs.
The answer choices are...
A.F = 0 newtons
B.F = -6.0 × 10-15 newtons
C.F = -9.6 × 10-15 newtons 
D.F = -3.0 × 10-16 newtons
E. F = -3.2 × 10-21 newtons

Krissy525 · Answer

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