Question

Consider the following relation.
4y+ √x = 4x + (x−1)^2
Evaluate the function found in the previous step at x = 1.
f(1) =

Answer 1

@vocaloid

Answer 2

y=f(1)
put x=1 and find the value of y.

Answer 3

y=f(1) = 4y+ √x = 4x + (x−1)^2

you mean ?

Answer 4

value of y at x=1 is f(1)

Answer 5

first substitute x=1 and find 4y,then y

Answer 6

f(1) = x=1

Answer 7

no,put x=1
\[4y+\sqrt{1}=4\times1+(1-1)^2\]
4y=?
y=?

Answer 8

y = x - 1/4

Answer 9

4y+1=4+0
4y=4-1=3
4y=3
y=3/4

Answer 10

f(1)=value of y at x=1 is 3/4