Question

Find the area.

Answer 1

Okay so the equation for the area of a trapezoid is
\(A=\dfrac{a+b}{2}h\)

Now, your height is the value of \(10\)
\(A=\dfrac{a+b}{2}(10)\)

The values of your \(a\) and \(b\) are \(10\) and \(12\)
\(A=\dfrac{10+12}{2}(10)\)

You can now solve for this
\(A=\dfrac{10+12}{2}(10)\)

\(A=11(10)\)

\(A=110\)

So your area of the trapezoid is `110`

Answer 2

Need help on this

Answer 3

You multiply length times width and then thats how u get your answer I am not allowed to answer it for you due to it's illegal on this site.

Answer 4

which sides are length and width

Answer 5

So, this equation contains 2 triangles and 1 square, which makes this equation

\(A=\dfrac{lw}{2}+\dfrac{bc}{2}+xy\)

\(A=\dfrac{5(11)}{2}+\dfrac{3(8)}{2}+8(8)\)

Simplify and solve
\(A=27.5+12+64\)

Which gives you
\(A=103.5\)
As your area