Question

Find the y-intercept for the parabola defined by this equation: y=4x^2-8x-5
Seperate the 2 values with a comma

Answer 1

can you show me how to solve it

Answer 2

@tranquility subject change to Mathematics please

Answer 3

oh i thought i was on mathematics

Answer 4

y-intercept is where the x-value is 0.
So plug in x = 0 and see what y-value you get.

Answer 5

Okay so, to solve for the y-int of a parabola, you need to replace \(x\) with \(0\)

\(y=4x^2-8x-5\)
\(y=4(0)^2-8(0)-5\)

So what would you get?

Answer 6

0-0-5

Answer 7

Which would give you?

Answer 8

(5,0)?

Answer 9

The y-int is (0,y), not (x,0), that's the x-int

Answer 10

(0,5)

Answer 11

Close, 0-0-5

0-0 is just 0, but what would you get from 0-5?

Answer 12

5

Answer 13

Close, nothing minus 5 is -5, not 5

Answer 14

So what would your y-int coordinate be?

Answer 15

wait so its (0,-5)

Answer 16

Correct ^^

Answer 17

thank you

Answer 18

No problem ^^