Find the y-intercept for the parabola defined by this equation: y=4x^2-8x-5
Seperate the 2 values with a comma

Question

Find the y-intercept for the parabola defined by this equation: y=4x^2-8x-5 
Seperate the 2 values with a comma

lifewmylilweeb · Answer

can you show me how to solve it

Extrinix · Answer

@tranquility subject change to Mathematics please

lifewmylilweeb · Answer

oh i thought i was on mathematics

minustempo · Answer

y-intercept is where the x-value is 0.
So plug in x = 0 and see what y-value you get.

Extrinix · Answer

Okay so, to solve for the y-int of a parabola, you need to replace $x$ with $0$

$y=4x^2-8x-5$
$y=4(0)^2-8(0)-5$

So what would you get?

lifewmylilweeb · Answer

0-0-5

Extrinix · Answer

Which would give you?

lifewmylilweeb · Answer

(5,0)?

Extrinix · Answer

The y-int is (0,y), not (x,0), that's the x-int

lifewmylilweeb · Answer

(0,5)

Extrinix · Answer

Close, 0-0-5

0-0 is just 0, but what would you get from 0-5?

lifewmylilweeb · Answer

5

Extrinix · Answer

Close, nothing minus 5 is -5, not 5

Extrinix · Answer

So what would your y-int coordinate be?

lifewmylilweeb · Answer

wait so its (0,-5)

Extrinix · Answer

Correct ^^

lifewmylilweeb · Answer

thank you

Extrinix · Answer

No problem ^^