Question

Help with math: https://snipboard.io/wrK7gS.jpg

Answer 1

To find the zeroes of the function, set the numerator equal to 0 and solve.
6x = 0
x = ??

To find the asymptotes, set the denominator equal to 0 and solve.
x^2 - 36 = 0
x = ??

Answer 2

vertical asymptotes

x=6, x=-6

horizontal asymptotes

y=0

zeros (0,0)

Answer 3

f(x) = 6x / ( x^2 - 36)

First factor

f(x) = 6x / ( x-6)(x+6)
Nothing cancels

Answer 4

x-6 = 0 x+6=0

x=6 x= -6

Answer 5

To find the zeros, we find where the numerator = 0

6x=0

x=0

Answer 6

Good job!

Answer 7

I was right

Answer 8

Yes, you were :)

Answer 9

Ok thanks