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Mathematics
kekeman:

Help with math: https://snipboard.io/wrK7gS.jpg

Tranquility:

To find the zeroes of the function, set the numerator equal to 0 and solve. 6x = 0 x = ?? To find the asymptotes, set the denominator equal to 0 and solve. x^2 - 36 = 0 x = ??

kekeman:

vertical asymptotes x=6, x=-6 horizontal asymptotes y=0 zeros (0,0)

kekeman:

f(x) = 6x / ( x^2 - 36) First factor f(x) = 6x / ( x-6)(x+6) Nothing cancels

kekeman:

x-6 = 0 x+6=0 x=6 x= -6

kekeman:

To find the zeros, we find where the numerator = 0 6x=0 x=0

Tranquility:

Good job!

kekeman:

I was right

Tranquility:

Yes, you were :)

kekeman:

Ok thanks

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