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Solve the rational equation x over 4 equals x squared over quantity 3x plus 3 and check for extraneous solutions. x = −3; x = 0 is an extraneous solution x = 0; x = −3 is an extraneous solution x = 0 and x = 3 x = 0 and x = −3
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im confused on this one idk what to pick
@ihelpuuhelpme
@tranquility
\(\dfrac{x}{4} = \dfrac{x^2}{3x+3}\) Any ideas on how to solve for x?
oh i alr know the answer its x <= (0,3) right?
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for*
that problem
yes, x =0, 3 An extraneous solution is when you solve the equation and you get a solution but when you plug back in the number, it doesn't make the equation true
i was thinking c
is the answer
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That is correct
thanks
you're welcome
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