Question

Read the following code:

n = 2
while(n < 5):
print(n)
n = n + 1

What output would be produced for the given values of n?

0 1 2 3 4
1 2 3 4 5
2 3 4
2 3 4 5

Answer 1

im confused

Answer 2

the program declares n to be 2

the while loop sets a condition: while n is less than 5, it runs these two lines:

print(n)
n = n + 1

the first line prints the value of n, then the next line re-assigns n to be n + 1

so you start with n = 2. the function will print 2, then it will re-assign n to be 2 + 1, or 3.

since n is now 3, which is still less than 5, the function runs again. keep running the function, writing what it prints out, while the conditions are met.

Answer 3

so this means its C? right?

Answer 4

good, the function starts at 2 and runs its last loop when n = 4, printing n = 4 and re-assigning n as 5 (which makes the loop fail to run again), so it is just 2 3 4

Answer 5

yeah makes sense, ill go with C