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muddy1300:
An arrow is shot vertically upward from a platform 39ft high at a rate of 167ft/sec. When will the arrow hit the ground? Use the formula: h=−16t2+v0t+h0.
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Vocaloid:
h0 is the initial height (39 ft) v0 is the initial velocity (167 ft/sec) Final height h is 0 since we want to know when the arrow reaches ground level Plug these into the equation and solve for t
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