a theater sells tickets for a concert. Tickets for lower level seats sell for $35 each and tickets for upper level seats sell for $25 each. The theater sells 350 tickets for $10.250

How many tickets of each type were sold

Question

a theater sells tickets for a concert. Tickets  for lower level seats sell for $35 each and tickets for upper level seats sell for $25 each. The theater sells 350 tickets for $10.250

How many tickets of each type were sold

bella2025 · Answer

yeah I dont know what im doing

dukedadon · Answer

Are there any answer choices?

Sailor · Answer

Ok. We can set up equations for the two different types of tickets. 
Tickets for the lower level seats: $$35x$$
Tickets for the upper level seats:$$25y$$
These are going to eventually be in the same equation, but the x and the y shows that they are two different things.

Sailor · Answer

Is 10.250 10 dollars and 25 cents or is is something else?

bella2025 · Answer

@dukedadon wrote:

Are there any answer choices?

no

bella2025 · Answer

@sailor wrote:

Is 10.250 10 dollars and 25 cents or is is something else?

no thats 10 dollars and 25 cents

Sailor · Answer

@bella2025 wrote:

@sailor wrote:

Is 10.250 10 dollars and 25 cents or is is something else?

no thats 10 dollars and 25 cents

Ok.

Sailor · Answer

Are you sure it's not 10,250?

Sailor · Answer

Because if we set up an equation like 35x+25y=10.250, it just wouldn't work.

Sock · Answer

Question, what grade are you in?

bella2025 · Answer

@sock wrote:

Question, what grade are you in?

9th

bella2025 · Answer

@sailor wrote:

Because if we set up an equation like 35x+25y=10.250, it just wouldn't work.

ok so then Ig its 10,250

Sock · Answer

@bella2025 wrote:

@sailor wrote:

Because if we set up an equation like 35x+25y=10.250, it just wouldn't work.

ok so then Ig its 10,250

can u take a ss of the question so we can see?

bella2025 · Answer

@sock wrote:

@bella2025 wrote:

@sailor wrote:

Because if we set up an equation like 35x+25y=10.250, it just wouldn't work.

ok so then Ig its 10,250

can u take a ss of the question so we can see?

Its on paper and my camera dont work

Sailor · Answer

Ok. Well then the first equation would be $35x + $25y = $10,250 and the second equation would be x + y = 350.

bella2025 · Answer

@sailor wrote:

Ok. Well then the first equation would be $35x + $25y = $10,250 and the second equation would be x + y = 350.

ok so then what would I do from there

Sailor · Answer

You would use the substitution method.

bella2025 · Answer

@sailor wrote:

You would use the substitution method.

plug 1 in for y and x

Sailor · Answer

Ok. On the second equation, you would get y on the other side. Then, you would plug 350-x into the equation $35x + $25y = $10,250.
$$35x + 25 (350 - x) = $10,250$$
$$35x + $8750 - 25x = $10,250$$
$$10x + $8750 = $10,250$$
Subtract 8,750 from both sides
$$10x = 1,500$$
Divide by 10 on each side.  You should get x = 150.

Sailor · Answer

You would then substitute that into the equation of y = 350 - x.
$$y=350-x$$
$$y = 350 - 150$$
$$y=200$$

Sailor · Answer

Therefore, x=150 and y=200. So, there were 150 tickets for the lower seats, and 200 tickets for the upper level seats.

Sailor · Answer

@bella2025 Hope this helps you out.

bella2025 · Answer

@sailor wrote:

@bella2025 Hope this helps you out.

thank you ive just had so much going on so for me not to answer im sorry

Sailor · Answer

@bella2025 wrote:

@sailor wrote:

@bella2025 Hope this helps you out.

thank you ive just had so much going on so for me not to answer im sorry

You're welcome.