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Mathematics 6 Online
lifewmylilweeb:

i need help

lifewmylilweeb:

lifewmylilweeb:

@mhanifa

lifewmylilweeb:

@itzlily

lifewmylilweeb:

@tranquility

mhanifa:

What is the context of this question? Seems its incomplete

lifewmylilweeb:

wdym

mhanifa:

If it is just what you attached, then the solution is: v(t) = the sum of f(t) and g(t)

lifewmylilweeb:

1 business day is 8 hours t represents time in hours f(t)=12(1.20)^t g(t)=-4.5t

lifewmylilweeb:

Add the two functions and call the resulting function v(t).

lifewmylilweeb:

?

mhanifa:

Yes

mhanifa:

Can you add the two?

lifewmylilweeb:

how

lifewmylilweeb:

14.4^t + 4.5t

mhanifa:

f(t)=12(1.20)^t g(t)=-4.5t v(t) = f(t) + g(t) = 12(1.20)^t + (-4.5t) = 12(1.20)^t - 4.5t

lifewmylilweeb:

huh?

mhanifa:

The first function is exponential and the second one is linear. If you are looking for simplification then there is no further simplification

lifewmylilweeb:

so

lifewmylilweeb:

im confused

mhanifa:

There is no value at this stage, just an equation

lifewmylilweeb:

so what is the answer

mhanifa:

v(t) = 12(1.20)^t - 4.5t

lifewmylilweeb:

so if i were to put this equation on a graph how would I

lifewmylilweeb:

is the equation linear, quadratic, exponential, or logarithmic

mhanifa:

You better use a graphing tool like desmos. It is a mixed function

lifewmylilweeb:

they want us using this edmentum graphing tool

mhanifa:

Can you copy the equation into this tool?

lifewmylilweeb:

no

lifewmylilweeb:

mhanifa:

It would be a custom function

mhanifa:

Does it allow manually adding/typing the function?

lifewmylilweeb:

typing

mhanifa:

But not copy-paste?

lifewmylilweeb:

we can copy and paste

mhanifa:

Ok, then you can copy here and paste into your tool

lifewmylilweeb:

If i paste this v(t) = 12(1.20)^t - 4.5t it will say it cannot be plotted

mhanifa:

Have you tried?

mhanifa:

.. as custom

mhanifa:

I am not familiar with this tool, sorry

lifewmylilweeb:

i got this

mhanifa:

This is the line and there is no variable in your equation. It is not what you need

mhanifa:

Try x instead of t, see if it works

lifewmylilweeb:

so

lifewmylilweeb:

v(x) = 12(1.20)^x- 4.5x or 12(1.20)^x- 4.5x

mhanifa:

Either should do

lifewmylilweeb:

lifewmylilweeb:

?

mhanifa:

Yes, good job

lifewmylilweeb:

so do you know what the initial value of the graph is

mhanifa:

It should be the value of v when t = 0 v(0) = 12(1.20)^0- 4.5(0) = 12*1 = 12

lifewmylilweeb:

so do i solve this equation

mhanifa:

It is solved for you: v(0) = 12 is the initial value

lifewmylilweeb:

oh thank you

lifewmylilweeb:

do you know how to find the final value

mhanifa:

Substitute t with 8 into equation and find the value of v(8). Remember it says 8 hours. The initial one was v(0) and the final should be v(8)

lifewmylilweeb:

which equation

lifewmylilweeb:

12(1.20)^x- 4.5x

mhanifa:

@lifewmylilweeb wrote:
12(1.20)^x- 4.5x
Yes

lifewmylilweeb:

12(1.20)^8-4.5(8)?

mhanifa:

Yes

mhanifa:

Let me know what you get

lifewmylilweeb:

I got 15

mhanifa:

It is close but not the exact answer

lifewmylilweeb:

we dont need the exact answer we need to know a answer close to it

lifewmylilweeb:

they asked "about" how much

mhanifa:

15.6 is the rounded number

mhanifa:

You may put 15 or 16. But you did it, congrats

lifewmylilweeb:

its too late i already submitted it 0.0

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