Mathematics
6 Online
lifewmylilweeb:
i need help
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lifewmylilweeb:
lifewmylilweeb:
@mhanifa
lifewmylilweeb:
@itzlily
lifewmylilweeb:
@tranquility
mhanifa:
What is the context of this question? Seems its incomplete
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lifewmylilweeb:
wdym
mhanifa:
If it is just what you attached, then the solution is:
v(t) = the sum of f(t) and g(t)
lifewmylilweeb:
1 business day is 8 hours
t represents time in hours
f(t)=12(1.20)^t
g(t)=-4.5t
lifewmylilweeb:
Add the two functions and call the resulting function v(t).
lifewmylilweeb:
?
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mhanifa:
Yes
mhanifa:
Can you add the two?
lifewmylilweeb:
how
lifewmylilweeb:
14.4^t + 4.5t
mhanifa:
f(t)=12(1.20)^t
g(t)=-4.5t
v(t) = f(t) + g(t) = 12(1.20)^t + (-4.5t) = 12(1.20)^t - 4.5t
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lifewmylilweeb:
huh?
mhanifa:
The first function is exponential and the second one is linear. If you are looking for simplification then there is no further simplification
lifewmylilweeb:
so
lifewmylilweeb:
im confused
mhanifa:
There is no value at this stage, just an equation
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lifewmylilweeb:
so what is the answer
mhanifa:
v(t) = 12(1.20)^t - 4.5t
lifewmylilweeb:
so if i were to put this equation on a graph how would I
lifewmylilweeb:
is the equation linear, quadratic, exponential, or logarithmic
mhanifa:
You better use a graphing tool like desmos. It is a mixed function
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lifewmylilweeb:
they want us using this edmentum graphing tool
mhanifa:
Can you copy the equation into this tool?
lifewmylilweeb:
no
lifewmylilweeb:
mhanifa:
It would be a custom function
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mhanifa:
Does it allow manually adding/typing the function?
lifewmylilweeb:
typing
mhanifa:
But not copy-paste?
lifewmylilweeb:
we can copy and paste
mhanifa:
Ok, then you can copy here and paste into your tool
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lifewmylilweeb:
If i paste this v(t) = 12(1.20)^t - 4.5t it will say it cannot be plotted
mhanifa:
Have you tried?
mhanifa:
.. as custom
mhanifa:
I am not familiar with this tool, sorry
lifewmylilweeb:
i got this
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mhanifa:
This is the line and there is no variable in your equation. It is not what you need
mhanifa:
Try x instead of t, see if it works
lifewmylilweeb:
so
lifewmylilweeb:
v(x) = 12(1.20)^x- 4.5x
or
12(1.20)^x- 4.5x
mhanifa:
Either should do
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lifewmylilweeb:
lifewmylilweeb:
?
mhanifa:
Yes, good job
lifewmylilweeb:
so do you know what the initial value of the graph is
mhanifa:
It should be the value of v when t = 0
v(0) = 12(1.20)^0- 4.5(0) = 12*1 = 12
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lifewmylilweeb:
so do i solve this equation
mhanifa:
It is solved for you:
v(0) = 12 is the initial value
lifewmylilweeb:
oh thank you
lifewmylilweeb:
do you know how to find the final value
mhanifa:
Substitute t with 8 into equation and find the value of v(8). Remember it says 8 hours. The initial one was v(0) and the final should be v(8)
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lifewmylilweeb:
which equation
lifewmylilweeb:
12(1.20)^x- 4.5x
mhanifa:
@lifewmylilweeb wrote:
12(1.20)^x- 4.5x
Yes
lifewmylilweeb:
12(1.20)^8-4.5(8)?
mhanifa:
Yes
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mhanifa:
Let me know what you get
lifewmylilweeb:
I got 15
mhanifa:
It is close but not the exact answer
lifewmylilweeb:
we dont need the exact answer we need to know a answer close to it
lifewmylilweeb:
they asked "about" how much
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mhanifa:
15.6 is the rounded number
mhanifa:
You may put 15 or 16. But you did it, congrats
lifewmylilweeb:
its too late i already submitted it 0.0