Simplify cube root of 7 over fifth root of 7. Will you guys help me.
Hello
Anybody know this
Help
Anybody?
I know it is a hard question.
Would you guys like answer choices?
Can I get someone to reply?
Can you right this down as exponents?
Here are the choices 7 to the power of 1 over 5 7 to the power of 8 over 15 7 to the power of 5 over 3 7 to the power of 2 over 15
This is not my question
How would you show the cube root of 7?
cube root of 7 over fifth root of 7
That is the best I can show you. Thanks for trying to help.
\[7^{1/3}\]
What about the 5th root?
Yor right here is the right question Simplify cube root of 7 over fifth root of 7
\[7^{1/3}/7^{1/5}\]
You need to use the following rule:
\[a^b/a^c=a^{b-c}\]
Can you apply this to your question?
I don't understand
\[7^{1/3}/7^{1/5}=7^{1/3-1/5}\] Can you find the exponent
One question are most users on here kids?
What is 1/3 - 1/5?
What?
I sorry I guess I am wasting your time.
1/3 - 1/5 = 5/15 - 3/15= 2/15
I meant I'm sorry
Can you guess the choice?
What do you think the answer is out of the choices I gave u
I think it is D.
What do you think?
I gave you the solution and you guessed it right
Thanks a lot! I will fan you.
You are welcome!
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