Question

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

7x + 2y = –1
7x + 2y = 1
14x + 4y = –1
14x + 4y = 1

Answer 1

\[slope~m=\frac{ y_{2}-y_{1} }{ x_{2}-x_{1} }\]
take either point J or K
and then use the formula
\[y-y_{1}=m(x-x_{1})\]
and simplify