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@AZ
Convert this into quadratic equation: x^2 - 16x + 63 = 0
Another way is graphing. Plot the graph of functions y = x^2 and y = 16x - 63 and take the x-coordinate of the intersection(s0
Let me know if you need help with either method.
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\[x ^{2}=16x-63\] \[x ^{2}-16x+63=0\] \[x^2-9x-7x+63=0\] x(x-9)-7(x-9)=0\] (x-9)(x-7)=0 x=?
@26millecai wrote:
use Mathway its a website :)
x= 9, 7
@chrisdjackson wrote:
x= 9, 7
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