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Mathematics 8 Online
CYBER257:

More help (sorry)

CYBER257:

1 attachment
CYBER257:

I need both angles pls!

Eveeeeeeeee14:

12*1/3

CYBER257:

so 12 and 33?

surjithayer:

let one angle=x other angle=180-x \[\frac{ 1 }{ 3 }x+12=180-x\] multiply by 3 x+36=540-3x x+3x=540-36 4x=504 x=504/4=126 one angle=126 second angle=180-26=154

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