If 18.5 grams of CuCl2 react with 22.8 grams of NaNO3, what mass of NaCl can be formed?

CuCl2 + NaNO3 → Cu(NO3)2 + NaCl
a
12.4 g NaCl

b
15.7 g NaCl

c
16.2 g NaCl

d
28.4 g NaCl

Question

If 18.5 grams of CuCl2 react with 22.8 grams of NaNO3, what mass of NaCl can be formed?

CuCl2 + NaNO3 → Cu(NO3)2 + NaCl
a
12.4 g NaCl

b
15.7 g NaCl

c
16.2 g NaCl

d
28.4 g NaCl

wrkwhrkhr · Answer

attachment

martai · Answer

what do u think it is ?

wrkwhrkhr · Answer

Well see,that's the point I am not fully sure.Though,I feel it could be letter choice b)15.7 g NaCl....?

martai · Answer

u are correct good job

wrkwhrkhr · Answer

Overall,thank you for the refresher I really needed it @martai .Thank you for the help,and have a good rest of your afternoon.

martai · Answer

@wrkwhrkhr wrote:

Overall,thank you for the refresher I really needed it @martai .Thank you for the help,and have a good rest of your afternoon.

np