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7^8 divide about 7^4
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\(\Large \dfrac {a^b}{a^c} = a^{b-c}\)
so i do 8-4?
\(\dfrac{7^8}{7^4} = ??\)
@tetsxpreme wrote:
so i do 8-4?
7^4?
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i think i get it now
7^4 is correct!
thank you
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