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Mathematics 17 Online
Kyky232:

What is the range of g(x)=3^(-x)

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Do you know how to find a range?

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Kyky232:

no

DRAK0:

Remove parentheses. 3 ^-x Use Negative Power Rule X^-6=1/x^a. ​ 1/3^x

surjithayer:

\[g(x)=3^{-x}=\frac{ 1 }{ 3^{x} }\ge 0 , ~\forall ~values~of~x\] Range:- all positive real numbers.

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