Question

Mathz grouping

Answer 1

Add and subtract the second term to the expression and factor by grouping.

Answer 2

Ik how to do grouping. Just somewhere in there I get stuck

Answer 3

you would get \[(x−2)(x ^{2}+1)\]

Answer 4

Okay. The part im stuck on is doing the second set of parenthesis.

Answer 5

you want me to explain?

Answer 6

Yes please.

Answer 7

ok
Factor by grouping
\[𝑥 ^{(3)}− 2 𝑥 {}^{(2)} + 𝑥 − 2\]
\[𝑥 ^{3} − 2 𝑥 ^{2} + 𝑥 − 2\]

Answer 8

do the same thing
\[x ^{3}−2x ^{2}+x−2\]
\[𝑥 ^{3} + 𝑥 − 2 𝑥 ^{2} − 2\]

Answer 9

okay

Answer 10

\[𝑥 ^{3} + 𝑥 − 2 𝑥 ^{2} − 2\]\[𝑥 ( 𝑥 ^{2} + 1 ) − 2 ( 𝑥 ^{2} + 1 ) \]

Answer 11

\[𝑥 ( 𝑥 ^{2} + 1 ) − 2 ( 𝑥 ^{2} + 1 )\] \[( 𝑥 − 2 ) ( 𝑥 ^{2} + 1 )\]

Answer 12

okay i get it now. thank you

Answer 13

:)

Answer 14

I gave you one earlier.