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thirty tickets were sold for a concert some at 60 cents and the rest at 1 dollar .if the total raised was 22 dollar how many had the cheaper tickets
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old question, answering to close. let x be the # of cheaper tickets and y the # of more expensive tickets. you can make a system of two equations to solve for these two unknowns. since there are 30 tickets, x + y = 30 the cheaper tickets are $0.60 and the more expensive tickets are $1. so the total revenue would be 0.6*x + 1*y = $22.00 solve the system for x
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