Question

thirty tickets were sold for a concert some at 60 cents and the rest at 1 dollar .if the total raised was 22 dollar how many had the cheaper tickets

Answer 1

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Answer 2

old question, answering to close.

let x be the # of cheaper tickets and y the # of more expensive tickets.

you can make a system of two equations to solve for these two unknowns.

since there are 30 tickets, x + y = 30
the cheaper tickets are $0.60 and the more expensive tickets are $1. so the total revenue would be 0.6*x + 1*y = $22.00

solve the system for x