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factor m^3-64
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Factor m3−64 m3−64 =(m−4)(m2+4m+16) Answer: (m−4)(m2+4m+16)
Since both terms are perfect cubes, factor using the difference of cubes formula
@ferrari wrote:
Factor m3−64
m3−64
=(m−4)(m2+4m+16)
Answer:
(m−4)(m2+4m+16)
nah
@vocaloid
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@ferrari wrote:
Factor m3−64
m3−64
=(m−4)(m2+4m+16)
Answer:
(m−4)(m2+4m+16)
aight got it
i wrote it in mathtype
Isn't that Symbolab?
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yup
yes. i used some of the work to do it.
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