Question

Help (graphing)

Answer 1

let
y=asin(x-b)+c
when x=0,y=-2
-2=asin(-b)+c
-2=-a sinb+c
x=\pi
-2=asin (\pi-b)+c
-2=a sinb+c
\[a\neq 0\]
-a sin b+c=a sin b+c
2a sin b=0
sin b=0
b=0
so y=a sin x+c
again when x=0,y=-2
-2=a sin 0+c
c=-2
y=a sin x-2
when \[x=\pi/2\]
y=1
1=a sin (\pi/2)-2
1+2=a*1
a=3
so function is y=3sin x-2