Question

subject
Mathematics, 07.12.2021 18:50 izzyisawesome5232
John and Elijah are both driving from New York City to Richmond. John leaves at 7:20 and averages 60 mph (miles per hour) on the way. Elijah leaves
at 7:30 and averages 62 mph on the way. The situation is modeled by this
system, where x is the number of hours after Elijah leaves and y is the
distance each will travel.
y= 60x + 10
y = 62x
How long after Elijah leaves will he pass John, and how far will they each have traveled.
y= 60x + 10
y = 62x

Answer 1

A. Elijah will not pass John, because he will never catch up with him.
B. Elijah will pass John after 2 hours, and they each will have traveled
128 miles.
C. Elijah will pass John after 5 hours, and they each will have traveled
310 miles.
D. Elijah will pass John after 4 hours, and they each will have traveled
248 miles.

Answer 2

John travels at 60mph and got a 10 minute head start ahead of Elijah, so his distance equation is y= 60x + 10
Elijah travels 62 mph, so his equation is y = 62x

Elijah will catch up to John at some point. At that point, their distances will be equal, so you can set the distance equations equal to each other.

60x + 10 = 62x
solve for x. that's the # of hours it'll take for Elijah to pass John.

Answer 3

so the answer would be C?

Answer 4

Yup good