Question

Which direction does the graph of the equation shown below open?
y^2+16y-4x+4=0

Answer 1

It didn't show a graph with the equation but the answer choices are
A.Left
B. Down
C. Right
D. Up

Answer 2

since the y is squared, not the x, that narrows us down to left or right

to determine between left vs. right, re-write the parabola in standard form by factoring/completing the square. the final equation should be in the form

(y-k)^2 = 4p(x-h), (where k and h can be positive, negative, or 0). if p > 0 the parabola will open right, if p < 0 it opens left.