Ask your own question, for FREE!
Mathematics 7 Online
WickedHeart:

Trigonometry Screenshot⬇️

WickedHeart:

Question:

WickedHeart:

Graph A:

1 attachment
WickedHeart:

Graph B:

1 attachment
WickedHeart:

Graph C:

1 attachment
WickedHeart:

Graph D:

1 attachment
WickedHeart:

Graph E:

1 attachment
WickedHeart:

Graph F:

1 attachment
WickedHeart:

Graph G:

1 attachment
WickedHeart:

Graph H:

1 attachment
WickedHeart:

Graph I:

1 attachment
WickedHeart:

There Done

WickedHeart:

Uh, Maybe this one?

1 attachment
WickedHeart:

Im terrible at this XD

jhonyy9:

do you know what mean sec theta ?

WickedHeart:

@jhonyy9 wrote:
do you know what mean sec theta ?
A right Angle ratio of hypotenuse and adjacent side?

jhonyy9:

@wickedheart wrote:
@jhonyy9 wrote:
do you know what mean sec theta ?
A right Angle ratio of hypotenuse and adjacent side?
exactly so how can use this is these cases to find the angle theta value ?

WickedHeart:

@jhonyy9 wrote:
@wickedheart wrote:
@jhonyy9 wrote:
do you know what mean sec theta ?
A right Angle ratio of hypotenuse and adjacent side?
exactly so how can use this is these cases to find the angle theta value ?
By using the pythagorean theorem ?

jhonyy9:

no use what you written above about what mean sec theta

WickedHeart:

@wickedheart wrote:
Oh so you find the ratio of \[\frac{ -12 }{ 5}\]

jhonyy9:

@wickedheart wrote:
@jhonyy9 wrote:
do you know what mean sec theta ?
A right Angle ratio of hypotenuse and adjacent side?
so using this what you above written sec theta = hyp. / adj. sec theta = -12 /5 = hyp. / adj. from this ratio result hypotenuse = ? and adjacent side = ?

WickedHeart:

Im stuck on adjacent

WickedHeart:

hypotenuse: \[ √ ( 5 ) ^2 − ( 3 ) ^2 = 4 \]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!