A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.

Angle A = 16
Angle B = 24

Find BC, the distance from Tower 2 to the plane, to the nearest foot.
Find CD the height of the plane from the ground, to the nearest foot.

Question

A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.

Angle A = 16
Angle B = 24

Find BC, the distance from Tower 2 to the plane, to the nearest foot.
Find CD the height of the plane from the ground, to the nearest foot.

Katya · Answer

thank you! can I also have the explanation of its okay?

MaxyDaKid · Answer

yea of course give me a sec to type it out

MaxyDaKid · Answer

B=180-24=156 (180 because thats how many degrees a line equals) 
ACB=180-156-16=8 
sin16/a=sin8/7600 
Then you have to solve for a
BC=15052

sin(24)=x/15052 
15052 sin(24)=x 
then you have to solve for x
 CD=1622ft