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Describe the end behavior of the given function. A. As x decreases, f(x) approaches negative infinity. B. As x increases, f(x) approaches infinity. C. As x increases, f(x) approaches -2. D. As x decreases, f(x) approaches 2.
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Think about what happens to this part of the function when x goes to infinity (2/3)^x As you keep multiplying (2/3) by itself infinite times, the number keeps shrinking down to 0, right? So with that in mind, what happens to the value of (2/3)^x - 2 as x keeps increasing?
If (2/3)^x approaches 0 as x increases to infinity Then (2/3)^x - 2 approaches 2 less than 0, or -2
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