Question

calculate the electric force that exists between two objects that are 0.500 m apart and carry charges of 0.00450 C and 0.00240 C is this the force attractive or repulsive ?

Answer 1

F = k(q1)(q2) / (r^2)

Where k is Coloumb’s constant (9 * 10^9) , q1 and q2 are the charges 0.00450 C and 0.00240 C, and r is the distance between the two charges (0.500m).

Plug in and evaluate F.

Now, the two charges are both positive (notice how both charge values are positive). Do like charges attract or repel each other?