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Macho14:
Math help please.
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jhonyy9:
use these properties of logarithms log a + log b = log a*b log a - log b = log a/b
jhonyy9:
and hope you know again this too \[xlog_{a} b = \log_{a} b^{x}\]
Macho14:
yeah, I do, I am just confused about why it tells me to write the answer without logs
jhonyy9:
what result you get there ?
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