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Mathematics 19 Online
Macho14:

Math help please.

Macho14:

1 attachment
jhonyy9:

use these properties of logarithms log a + log b = log a*b log a - log b = log a/b

jhonyy9:

and hope you know again this too \[xlog_{a} b = \log_{a} b^{x}\]

Macho14:

yeah, I do, I am just confused about why it tells me to write the answer without logs

jhonyy9:

what result you get there ?

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