A rancher wants to fence in an area of 3000000 square feet in a rectangular field and then divide it in half with a fence down the middle parallel to one side. What is the shortest length of fence that the rancher can use?

Let length of field= l and width of field=w Area, A = lw Length of fence= P=2l+3w \[P=2l+\frac{ 3A }{ l }\] \[\frac{ dP }{ dl }= ........\] Then set \[\frac{ dP }{ dl }=0\] and you'll get the minimum length........

\[\frac{ dP }{ dl }=2+\frac{ -3A }{ l^2}\] \[\frac{ dP }{ dl }=0~gives\] \[2-\frac{ 3A }{ l^2 }=0\] \[2l^2=3A\] \[2l^2=3\times3000000\] \[2l^2=9000000\] \[l^2=4500000\] \[l=\sqrt{4500000}=1500\sqrt{2}\] \[\frac{ d^2P }{ dl^2 }=0+\frac{ 6A }{ l^3 }>0 ~for~l=1500\sqrt{2}~ft\] so P is minimum at this value. \[w=\frac{ 3000000 }{ 1500\sqrt{2}}=\frac{ 2000 }{ \sqrt{2} }=1000\sqrt{2}\] \[shortest~length~P=2l+3w=2\times 1500\sqrt{2}+3\times 1000\sqrt{2}=6000\sqrt{2}~ft.\] \[\approx 8485.2814~ft\]

Join our real-time social learning platform and learn together with your friends!