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lakeawilliams:
What is the solution to StartFraction 5 over 6 EndFraction x minus one-third greater-than 1 and one-third? x > StartFraction 25 over 18 EndFraction x < StartFraction 25 over 18 EndFraction x > 2 x < 2
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Vocaloid:
(5/6)x - (1/3) > (1 and 1/3)? First I’d rewrite 1 and 1/3 as 1 + 1/3 Then multiply both sides of the inequality by 6 to eliminate all the denominators. Remember to distribute 6 across 1 + 1/3 From there, isolate x
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