Question

A container of water is knocked off a 10.00–meter–high ledge with a horizontal velocity of 1.00 meters/second. Calculate the time it takes for the container to reach the ground.

Answer 1

delta y = v0 * t + (1/2)at^2

the cliff is 10.0m, so delta y = 10.0

Considering the y-direction only, the initial velocity is 0, so v0 = 0

a is the acceleration due to gravity (9.81 m/s/s)

Plug in the appropriate quantities and solve for t.