Question

Triangle XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z'. What is the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′?
A.
7 units
B.
25 units
C.
5 units
D.
units

Answer 1

let's simply focus on one point, X.



notice how, if we move point X 4 units up and 3 to the left to get to X', we make a right triangle where the distance is the hypotenuse. the distances 4 and 3 are the legs of the triangle.

therefore, we can use the pythagorean theorem to find the distance between X and X'.

4^2 + 3^2 = c^2

solve for c.

*note that this logic also applies to Y and Z, or any corresponding points when a shape is translated.