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A box contains 6 red and 5 blue marbles. Another box contains 5 red and 8 blue marbles. One box is selected at random and from that bag, one marble is drawn. What is the probability that the marble drawn is blue?
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consider each box one at a time assuming the two boxes are chosen randomly w/ equal probability, the probability of picking one box is (1/2). for the first box, there are 6 red and 5 blue (for a total of 11) so the probability of getting blue for that box is (5/11). the probability of picking this box *and* getting a blue marble is therefore (1/2)*(5/11). repeat this logic w/ the other box. then add the two probabilities.
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