Question

More math: https://snipboard.io/4l2TBE.jpg

Answer 1

Thats blocked for me :<

Answer 2

That sucks

Answer 3

how u use mathway i was going to too but i could not find the symbol

Answer 4

\[r=-\frac{ 3 }{ 8 }\]
\[\left| r \right|=\frac{ 3 }{ 8 }<1\]
it is an infinite G.P. with r=-3/8
\[first~term~a=10\left( \frac{ -3 }{ 8 } \right)^1=-\frac{ 30 }{ 8}\]
\[S _{\infty}=\frac{ a }{ 1-r}=\frac{ \frac{ -30 }{ 8} }{ 1-\left( \frac{ -3 }{8} \right) }=\frac{ \frac{ -30 }{ 8 } }{ \frac{ 11 }{ 8 }}=\frac{ -30 }{ 11 }\]

Answer 5

Oh so it is C.) -30/11