Question

Please help me! I need help with Trigonometry:



Plane A takes off at a 13° angle from the runway, and plane B takes off at a 9° angle from the runway. Which plane reaches a greater horizontal distance from the airport when the plane reaches an altitude of 10,000 feet? Round the solutions to the nearest whole number.

Plane A because it was 43,315 feet away
Plane A because it was 63,925 feet away
Plane B because it was 44,454 feet away
Plane B because it was 63,138 feet away

Answer 1

@jhonyy9 please help

Answer 2

\[\frac{ 10000 }{ x1 }=\tan 13\]
\[x1=10000 ~\cot~13=10000 \cot(90-77)=10000 \tan77\approx 43315~ft\]
\[\frac{ 10000 }{ x2 }=\tan 9\]
\[x2=10000 \cot 9=10000\cot(90-81)=10000 \tan 81\approx 63138 ft\]
Plane B because it was 63138 ft away.