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Find the cosine of an angle in the second quadrant whose cosecant is 5/3. A) 3/5 B) -3/5 C)-4/5 D) 4/5 E) -4/3
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Sketch the triangle in QII. csc(x) = 1/sin(x) = hypotenuse/opposite = 5/3 This is a 3-4-5 triangle so the adjacent side must be 4. ***however*** since we are in QII the cos is negative and the adjacent side is actually treated as -4 in the formula. From there it’s a straightforward cos(theta) = adjacent/hypotenuse calculation.
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