Question

helpp

Answer 1

Do you got to find the variable?

Answer 2

So plug X=6 in to find your angles

Answer 3

Ok if I am doing this correctly the equation would be set up as 6x-12=3x+30 and you combine like terms.

Answer 4

Ok if I am doing this correctly the equation would be set up as 6x-12=3x+30 and you combine like terms.

Answer 5

If that's right. I wasn't really good at geometry

Answer 6

no its not correct, thank you tho

Answer 7

I'm sorry. I wasn't really good at geometry

Answer 8

nah its fine, geometry is hard

Answer 9

Yep. But Algebra 2 is easy

Answer 10

mhm algebra isnt that hard, just takes memory.

Answer 11

Yep

Answer 12

If you need any more simplification hmu in DMs so I don't get in trouble again lol

Answer 13

alr thx

Answer 14

np

Answer 15

Leiland didn't really explain this but the way he got 90 was from the first thing they noted with the givens.

What it stated is basically line OA is perpendicular to line OC (the upside down T indicates 'perpendicular.') If this is true, then angle AOC must equal 90, as all right angles are created by perpendicular lines, and they equal 90. So therefore the angles constituting that right angle must equal 90. Therefore you can equate them to 90 and solve for the variables.

Answer 16

So I got a question. How do you you solve that without saying the answer?

Answer 17

@shadow ?

Answer 18

I've figured it out nvm.

Answer 19

Ok the way you do it is

Answer 20

6x-12+3x+30=90

Answer 21

When you get what x equals you times it to AOB and that will be your answer