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what is the value of x2 + 2y ÷ w + 3z for w = 2, x = 5, y = 8, and z = 3?
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all you have to do is plug the numbers into the equation so... x^2 + 2y ÷ w + 3z x = 5 y = 8 z = 3 w = 2 Plug x,y and z in, like 5(2) +2(8) ÷ 2 + 3(3) Then solve: 10 + 16 ÷ 2 + 9 26 ÷ 2 + 9 13 + 9 22 So the value is 22
@oliver69 wrote:
all you have to do is plug the numbers into the equation so...
x^2 + 2y ÷ w + 3z
x = 5
y = 8
z = 3
w = 2
Plug x,y and z in, like
5(2) +2(8) ÷ 2 + 3(3)
Then solve:
10 + 16 ÷ 2 + 9
26 ÷ 2 + 9
13 + 9
22
So the value is 22
x^2 this mean x squared
Your equation actually should be : \[5^2+2(8)\div 2+3(3)\] \[5^2=25\] \[2(8)=16\] \[25+16=41\] For the second part of the equation : \[2+3(3)=2+9=11\] \[41 \div 11= 3.72\]
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