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A tower on one side of a river is directly east and north of points A and B, respectively, on the other side of the river. The top of the tower has angles of elevation α and β from A and B, respectively, as shown in the image. Let d be the distance between A and B. Assuming that both sides of the river are are at the same elevation, show that the height h of the tower is h=d/√cot^2a+cot^2b
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Can I see the image, please?
yes
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Ok thank you.
@astrid1
well that sucks
My solution is attached. If you’re having any trouble understanding my work/handwriting please ask.
thanks so much bruh. i understand it
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