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The measures of the angles in △ABC are given by the expressions in the table. Find the value of x. Then find the m∠B and m∠C. (I attached a screenshot)
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sum of three angles of a triangle=180 add the three and find the value of x then find angles B and C
@surjithayer wrote:
sum of three angles of a triangle=180
add the three and find the value of x
then find angles B and C
A+B+C=65+(3x-10)+2x=180 ?
@surjithayer wrote:
A+B+C=65+(3x-10)+2x=180
?
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65+3x-10+2x=180 5x+55=180 5x=180-55=125 x=125/5=25 \[\angle B=3x-10=3(25)-10=75-10=65\] \[\angle C=2x=2(25)=50\]
@surjithayer wrote:
65+3x-10+2x=180
5x+55=180
5x=180-55=125
x=125/5=25
\[\angle B=3x-10=3(25)-10=75-10=65\]
\[\angle C=2x=2(25)=50\]
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