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an accepted relationship between stopping distance, d in feet, and the speed of a car, in mph, is d(v)=1.2v+o.o4v^2 on dry, level concrete. a) how many feet will it take a car traveling 50 mph to stop on dry, level concrete? b) if an accident occurs 250 feet ahead, what is the maximum speed at which one can travel to avoid being involved in the accident?
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