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can one of yall help me with my last math question?
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for A \[area=\pi r^2=\pi \times (4)^2=16\pi=16\times 3.14=50.24 mi^2\] for B \[area=\pi(r)^2=3.14\times(8.05)^2\approx203.48 ~km^2\] C. \[ or ~A~50.24\times (1.61)^2\approx 123.23~mi^2\] so B covers more area. D. scale factor for area from A to B \[=\left( \frac{ \pi \times(8.05)^2 }{ \pi \left( 4\times1.61 \right)^2 } \right)=\left( \frac{ 8.05 }{ 4.64} \right)^2\approx3\]
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