Question

help with this please https://prnt.sc/mOrxpzeDFSER

Answer 1

@vocaloid

Answer 2

it blocked

Answer 3

\[CI=x̄\pm z \frac{ s }{ \sqrt(n) }\]where x bar is the mean (given in the problem as 110), s is the standard deviation (given in the problem as 9), z is the confidence level (which will depend on the confidence level. for a) 98%, z would be 2.33, and n is the sample size (for a), given as 23). plug in the appropriate values to find the upper and lower bounds.

z-value table: https://www.six-sigma-material.com/images/CommonCLZvalues.png