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For part A, just add and combine all like terms for the 3. So: \[ (3x^2 -2) +(x^2) +(2xy+5) \] Then just subtract whatever you get from above from the original equation provided.
\[(6x^2 -2xy+8) -(4x^2 + 2xy+3) \]
@luigi0210 wrote:
\[(6x^2 -2xy+8) -(4x^2 + 2xy+3) \]
@luigi0210 wrote:
For part A, just add and combine all like terms for the 3.
So:
\[ (3x^2 -2) +(x^2) +(2xy+5) \]
Then just subtract whatever you get from above from the original equation provided.
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Hmm not quite
@luigi0210 wrote:
\[(6x^2 -2xy+8) -(4x^2 + 2xy+3) \]
2x^2 - 4xy + 5.
?
Yes, that should be it. Unless I suck at math now.
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@anoob wrote:
Yes, that should be it. Unless I suck at math now.
how about part b..
@anoob
The one you solved was part B Part A was just adding the three equations into one
@anoob wrote:
The one you solved was part B
Part A was just adding the three equations into one
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Guess I don't remember how to combine like terms apparently. But since they gave you the answer for part A, just subtract that from \[6x^2-2xy+8\]
@anoob wrote:
Guess I don't remember how to combine like terms apparently.
But since they gave you the answer for part A, just subtract that from \[6x^2-2xy+8\]
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